python - Storing a process object in multiprocessing Manager.dict() -

i have created sample program generalize issue facing

import multiprocessing multiprocessing import manager  def f (_print):     print _print     manager = multiprocessing.manager()     dict = manager.dict()     dict['process_obj'] = multiprocessing.current_process()     print dict  if __name__ == '__main__':     process = multiprocessing.process(target=f, args= ('hello function', ))     process.start()     process.join() 

so how store process object in multiprocessing manager.dict()?

i assume you're talking getting error:

hello function process process-1: traceback (most recent call last):   file "/usr/local/lib/python2.7/multiprocessing/process.py", line 258, in _bootstrap     self.run()   file "/usr/local/lib/python2.7/multiprocessing/process.py", line 114, in run     self._target(*self._args, **self._kwargs)   file "mp2.py", line 8, in f     dict['process_obj'] = multiprocessing.current_process()   file "<string>", line 2, in __setitem__   file "/usr/local/lib/python2.7/multiprocessing/managers.py", line 758, in _callmethod     conn.send((self._id, methodname, args, kwds)) picklingerror: can't pickle <type 'instancemethod'>: attribute lookup __builtin__.instancemethod failed 

(it's idea include "what got" , "what expected instead" in question).

the fundamental problem here multiprocessing.current_process() returns instance method. instance methods don't pickle properly, , multiprocessing has save (pickle) , load (unpickle) shared data items communicate values 1 process another. see, e.g., can't pickle <type 'instancemethod'> when using python's multiprocessing pool.map() , overcoming python's limitations regarding instance methods. note in particular 1 of answers in second: might better figure out state send/share, rather entire instance. instance, if ident of process suffices, can this:

    dict['process_obj'] = multiprocessing.current_process().ident 

which works fine.