i making django project, business directory. here have used absoulate paths template rendering, thnk might create problem in future. please codes , suggest me how solve problem not create problem in future.
please help
my models.py is::
from django.db import models class directory(models.model): bussiness_name = models.charfield(max_length=300) description = models.charfield(max_length=900) number = models.charfield(max_length=100) web_url = models.charfield(max_length=800) catogory = models.charfield(max_length=200) def __unicode__(self): return self.bussiness_name class adress(models.model): directory = models.foreignkey(directory) adress_name = models.charfield(max_length=300) def __unicode__(self): return self.adress_name class photos(models.model): directory = models.foreignkey(directory) photo_path = models.charfield(max_length=100) photo_name = models.charfield(max_length=100) def __unicode__(self): return self.photo_name my view.py ::
# create views here. django.http import httpresponse crawlerapp.models import directory crawlerapp.models import adress crawlerapp.models import photos django.template import context, loader django.shortcuts import render def index(request): directory_list = directory.objects.all() t=loader.get_template('c:/python27/django/crawler/templates/crawlertemplates/index.html') c = context({'directory_list': directory_list,}) return httpresponse(t.render(c)) def contactus(request): directory_list = directory.objects.all() t=loader.get_template('c:/python27/django/crawler/templates/crawlertemplates/contactus.html') c = context({'directory_list': directory_list,}) return httpresponse(t.render(c)) def search(request): if 'what' in request.get , request.get['what']: = request.get['what'] crawlerapp = directory.objects.filter(catogory__icontains=what) return render(request, 'c:/python27/django/crawler/templates/crawlertemplates/search.html', {'crawlerapp': crawlerapp, 'query': what}) elif 'who' in request.get , request.get['who']: = request.get['who'] crawlerapp = directory.objects.filter(bussiness_name__icontains=who) return render(request, 'c:/python27/django/crawler/templates/crawlertemplates/search.html', {'crawlerapp': crawlerapp, 'query': who}) else: message = 'you submitted empty form.' return httpresponse(message) and urls.py is::
from django.conf.urls import patterns, include, url # uncomment next 2 lines enable admin: django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # examples: # url(r'^$', 'crawler.views.home', name='home'), # url(r'^crawler/', include('crawler.foo.urls')), # uncomment admin/doc line below enable admin documentation: # url(r'^admin/doc/', include('django.contrib.admindocs.urls')), # uncomment next line enable admin: url(r'^admin/', include(admin.site.urls)), url(r'^crawlerapp/$', 'crawlerapp.views.index'), url(r'^crawlerapp/contactus/$', 'crawlerapp.views.contactus'), url(r'^crawlerapp/search/$', 'crawlerapp.views.search'), ) i have 3 html pages index, contactus, , search. please suggest alternative of absolute path create no errors if else clones github , try run it.
please solve this.
you should list you're template directories in setting.py files, in template_dirs list.
whether or not, should dynamically generate absolute path using os.path module's function.
os.path.abspath(__file__) will return absolute path file it's called in.
os.path.dirname('some/path') will return path last directory in 'some/path'
by combining them can absolute pathes remain accurate on different systems, eg
os.path.abspath(os.path.dirname(os.path.dirname(__file__))) will return absolute path directory 1 level above 1 containing current file.
go read docs os.path module. you'll need use os.path.join well.
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