30, 40 , 'n' such every number factor of product of other 2 number. if 'n' positive integer , difference between maximum value of 'n' , minimum value of 'n'?
now, since says n factor of product of other 2 numbers, max value n can take 1200 right?
i guess hcf give minimum value of n
listing factors of 30 , 40
30 -> 1,2,3,5,6,10,15,30
40 -> 1,2,4,5,8,10,20,40
hcf(30,40) -> 10
therfore, difference 1200-10 => 1190..
but answer given 1188...where going wrong?
your approach wrong. greatest common divisor of 30 , 40 not smallest n
.
you looking smallest integer n > 0
satisfies 40*n = 0 (mod 30)
, 30*n = 0 (mod 40)
.
for first equation, result n_1 = 3
. second equation, n_2 = 4
. smallest n
satisfy both equations least common multiple of n_1
, n_2
-- in case, n = 12
.
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