printing - Print conditional line depend on line above in unix -

dear stackoverflower,

i have project collecting data log file, , want collect data if line above match condition

for example, log data :

a1/apt "msbna1 013/088/" 341 130510   1756      h'0000-dba4 m3ua destination inaccessible a1/apt "msbna1 013/088/" 722 130702   1644      h'0000-2e2b event reporting threshold reached a1/apt "msjam2 106/00/0" 018 130118   0137      h'0000-001b blade source cp 02 m3ua destination inaccessible a1/apt "msjam2 106/00/0" 020 130227   1144      h'0000-001e blade source cp 10 m3ua destination inaccessible 

i want print out using condition :

-if line a1/apt... , source... print line below

-if line below blade, no need print

initially use command :

grep -a 1 a1 [file name] 

but work a1/apt line only, not source

any guys appreciate, thank much