linux - How to run bash script when a program open in liunx -

is there way execute bash script when click program netbeans or dropbox on ubuntu , execute bash script when exit

my idea create bash script on cronjob @reboot check every second if program exist in current processes

#!/bin/bash nameofprogram="netbeans" while [[ true ]];     countofprocess=$(ps -ef |grep $nameofprogram | wc -l)     if [[ $countofprocess -gt 1 ]];         #execute bash      fi     sleep 1 done 

but think idea not best ,is there better way achieve it?

a better approach wrap executable in script. means put script name of program in path (probably $home/bin) , linux use instead of real executable.

now can execute real program using:

/usr/bin/netbeans "$@" 

so execute real executable, put absolute path in front of name. odd "$@" pass on arguments might have given script.

put loop around this:

while [[ true ]];     /usr/bin/netbeans "$@" done 

but there problem: can't exit program anymore. try, restarts. if want restart when crashes:

while [[ true ]];     /usr/bin/netbeans "$@" && exit 0 done 

as long program exits because of error, restarted. if quit it, script stop.