c - Understanding fgetc program -

i'm reading book c programming , don't understand shown example. or more precisely don't understand why works because think shouldn't.

the code simple, reads content of text file , outputs in output area. far understand it, think the

 ch = fgetc(stream); 

ought inside while loop, because reads 1 int time? , needs read next int after current 1 has been outputted. well, turns out code indeed works fine hope explain fallacy me. thanks!

#include <stdio.h>  int main(int argc, char *argv[]) {     file *stream;     char filename[67];     int ch;     printf("please enter filename?\n");     gets(filename);     if((stream = fopen(filename, "r")) == null) {         printf("error opening file\n");         exit(1);     }      ch = fgetc(stream);     while (!feof(stream)) {         putchar(ch);         ch = fgetc(stream);     }      fclose(stream); } 

i think confuse because of feof():

doc: int feof ( file * stream );

checks whether end-of-file indicator associated stream set, returning value different 0 if is.

this indicator set previous operation on stream attempted read @ or past end-of-file.

   ch = fgetc(stream);      <---"read current symbol file"     while (!feof(stream)) { <---"check eof read/returned last fgetc() call"         putchar(ch);        <---"output lasts read symbol, not eof"         ch = fgetc(stream); <---"read next symbols file"     }    <-- control reach here when eof found    

a better way write loop like:

while((ch = fgetc(stream))!= eof){ <--" read while eof not found"    putchar(ch);   <-- "inside loop print symbol not eof" } 

additionally, note: int fgetc ( file * stream );

returns character pointed internal file position indicator of specified stream. internal file position indicator advanced next character.

if stream @ end-of-file when called, function returns eof , sets end-of-file indicator stream (feof).

if a read error occurs, function returns eof , sets error indicator stream (ferror).